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Copy pathhasSubTree.cc
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177 lines (146 loc) · 4.46 KB
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Copy pathhasSubTree.cc
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177 lines (146 loc) · 4.46 KB
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#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct BinaryTreeNode
{
int nValue;
struct BinaryTreeNode *pLeft;
struct BinaryTreeNode *pRight;
} BinaryTreeNode;
BinaryTreeNode* CreateTreeNode(int value);
void ConnectTreeNode(BinaryTreeNode* pParent, BinaryTreeNode* pLeft, BinaryTreeNode* pRight);
void DestroyTree(BinaryTreeNode *pRoot);
bool HasSubTree(BinaryTreeNode *pRoot1, BinaryTreeNode *pRoot2);
bool DoesTree1HasTree2(BinaryTreeNode *pTree1, BinaryTreeNode *pTree2);
int main()
{
int m, n;
while(scanf("%d%d", &m, &n) != EOF){
//创建树节点的数组,数组的每个元素是一个树指针
BinaryTreeNode **pTree1 = (BinaryTreeNode**) malloc(m * sizeof(unsigned long));
BinaryTreeNode **pTree2 = (BinaryTreeNode**) malloc(n * sizeof(unsigned long));
int tValue;
//创建二叉树A
//输入二叉树节点值
for(int i = 0; i < m; i++){
if(scanf("%d", &tValue) < 1)
perror("input error");
pTree1[i] = CreateTreeNode(tValue);
}
//将节点连接成特定结构的二叉树
int tNum, leftNodeIndex, rightNodeIndex;
for(int i = 0; i < m; i++){
if(scanf("%d", &tNum) < 1)
perror("input error");
if(tNum == 1){
if(scanf("%d", &leftNodeIndex) < 1)
perror("input error");
ConnectTreeNode(pTree1[i], pTree1[leftNodeIndex-1], NULL);
}
else if(tNum == 2){
if(scanf("%d%d", &leftNodeIndex, &rightNodeIndex) < 2)
perror("input error");
ConnectTreeNode(pTree1[i], pTree1[leftNodeIndex-1], pTree1[rightNodeIndex-1]);
}
}
//创建二叉树B
//输入二叉树节点值
for(int i = 0; i < n; i++){
if(scanf("%d", &tValue) < 1)
perror("input error");
pTree2[i] = CreateTreeNode(tValue);
}
//将节点连接成特定结构的二叉树
for(int i = 0; i < n; i++){
if(scanf("%d", &tNum) < 1)
perror("input error");
if(tNum == 1){
if(scanf("%d", &leftNodeIndex) < 1)
perror("input error");
ConnectTreeNode(pTree2[i], pTree2[leftNodeIndex-1], NULL);
}
else if(tNum == 2){
if(scanf("%d%d", &leftNodeIndex, &rightNodeIndex) < 2)
perror("input error");
ConnectTreeNode(pTree2[i], pTree2[leftNodeIndex-1], pTree2[rightNodeIndex-1]);
}
}
//确定树的根节点
/*
* 注意:如果树为空,则pTree=NULL,此时并未pTree[0]分配空间
* 此时在任何地方引用pTree[0]都会出现错误
* 所以不要直接把pTree[0]直接当做根节点来用,因为树为空时,pTree[0]不等于NULL,而是不存在
*/
BinaryTreeNode *pRoot1 = NULL;
BinaryTreeNode *pRoot2 = NULL;
if(m > 0)
pRoot1 = pTree1[0];
if(n > 0)
pRoot2 = pTree2[0];
//判断树A是否包含数B
if(HasSubTree(pRoot1, pRoot2))
printf("YES\n");
else
printf("NO\n");
//释放树节点所占空间
DestroyTree(pRoot1);
DestroyTree(pRoot2);
pRoot1 = NULL;
pRoot2 = NULL;
//释放树所占空间
free(pTree1);
free(pTree2);
pTree1 = NULL;
pTree2 = NULL;
}
}
bool HasSubTree(BinaryTreeNode *pRoot1, BinaryTreeNode *pRoot2)
{
bool result = false;
if(pRoot1 == NULL || pRoot2 == NULL)
return result;
if(pRoot1->nValue == pRoot2->nValue)
result = DoesTree1HasTree2(pRoot1, pRoot2);
if(!result)
result = HasSubTree(pRoot1->pLeft, pRoot2);
if(!result)
result = HasSubTree(pRoot1->pRight, pRoot2);
return result;
}
bool DoesTree1HasTree2(BinaryTreeNode *pTree1, BinaryTreeNode *pTree2)
{
if(pTree2 == NULL)
return true;
if(pTree1 == NULL)
return false;
if(pTree1->nValue != pTree2->nValue)
return false;
return DoesTree1HasTree2(pTree1->pLeft, pTree2->pLeft) &&
DoesTree1HasTree2(pTree1->pRight, pTree2->pRight);
}
BinaryTreeNode* CreateTreeNode(int value)
{
BinaryTreeNode *pTreeNode = (BinaryTreeNode*) malloc(sizeof(BinaryTreeNode));
pTreeNode->nValue = value;
pTreeNode->pLeft = NULL;
pTreeNode->pRight = NULL;
return pTreeNode;
}
void ConnectTreeNode(BinaryTreeNode* pParent, BinaryTreeNode* pLeft, BinaryTreeNode* pRight)
{
if(pParent == NULL)
return;
pParent->pLeft = pLeft;
pParent->pRight = pRight;
}
void DestroyTree(BinaryTreeNode *pRoot)
{
if(pRoot != NULL){
BinaryTreeNode *pLeft = pRoot->pLeft;
BinaryTreeNode *pRight = pRoot->pRight;
free((void*)pRoot);
pRoot = NULL;
DestroyTree(pLeft);
DestroyTree(pRight);
}
}