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217 changes: 217 additions & 0 deletions homeworks/JP_week2_hw.ipynb
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{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"## ❌ DO NOT EDIT - MAKE A COPY\n",
"# Q1: Alphabet Slices\n",
"* Store the first ten letters of the alphabet in a list.\n",
"* Use a slice to print out the first three letters of the alphabet.\n",
"* Use a slice to print out any three letters from the middle of your list."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve Alphabet slices here. \n",
"## Extra Credit: Do this without 'hard coding' the alpahbet.\n",
"\n",
"\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Q2: Covert all the rapper names to title case and save them into a new different list. \n",
"Example: **lil wayne** becomes **Lil Wayne**"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve rapper names here\n",
"rappers = ['lil wayne', 'nicki minaj', 'drake']\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Q3: Write a function that takes a number and returns:\n",
"* True if the input number is even.\n",
"* False if the input number is odd."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve problem here\n",
"\n",
"def even_odd(lst):\n",
" pass # replace this with your code\n",
" # return something"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Q4: Find the sum and the average of this list of numbers.\n",
"\n",
"Try doing this using a loop. Then try doing this without using a loop. "
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve problem here:\n",
"\n",
"my_list = [1, 5, 10, 55, 88, 44, 42, 50, 20, 38]\n",
"list_sum = ???\n",
"list_avg = ???\n",
"\n",
"\n",
"# Keep this as your last line in this cell.\n",
"print(list_sum, list_average)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Q5: \n",
"## Write a function that takes a list and returns a new list that has all the duplicates removed.\n",
"\n",
"Example input and expected output:\n",
"- input = `[\"Michele\", \"Robin\", \"Sara\", \"Michele\"]`\n",
"- expected output = `['Michele', 'Robin', 'Sara']`\n"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve problem here:\n",
"\n",
"names = [\"Michele\", \"Robin\", \"Sara\", \"Michele\"]\n"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Q6: Write a function that takes a list of numbers \n",
"(for example, `a = [5, 10, 15, 20, 25]`) and returns a new list of only the first and last elements of the given list.\n",
"\n",
"Example input and expected output:\n",
"- input = `[5, 10, 15, 20, 25]`\n",
"- expected output = `[5, 25]`"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve problem here:\n",
"input_list = [5, 10, 99, 20, 25]"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Q7: \n",
"## Implement a function that takes as input three variables, and returns the largest of the three. \n",
"### Try doing this without using the `max()` function!\n",
"\n",
"_**Note:** all three input numbers will always be different, no need to account for a tie._\n",
"\n",
"Example input and expected output:\n",
"- input: `your_function(1, 5, 10)`\n",
"- expected output: `10`"
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve Problem here:\n",
"\n",
"def my_max(a, b, c):\n",
" # Fill in your code below and return max value of a, b, c\n",
" "
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Test to see if your function works properly.\n",
"my_max(1, 5, 10)"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"# Q8: Write a function that takes a number as input and returns the following:\n",
"* If the input is divisible by three, return `'fizz'`\n",
"* If the input is divisible by five, return `'buzz'`\n",
"* If the input is divisible by three and by five, return `'fizzbuzz'`\n",
"* If the input is not divisible by three or five, return `None`."
]
},
{
"cell_type": "code",
"execution_count": null,
"metadata": {},
"outputs": [],
"source": [
"# Solve Problem fizzbuzz here:\n"
]
}
],
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"version": 3
},
"file_extension": ".py",
"mimetype": "text/x-python",
"name": "python",
"nbconvert_exporter": "python",
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