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19 changes: 18 additions & 1 deletion src/apple.c
Original file line number Diff line number Diff line change
@@ -1,17 +1,34 @@
#include <stdio.h>


//更新:ファイルの入れ替えをしました
int n;
int k;
int A[100000];

int p(int i1, int i2, int i3,int X[]){
int sum = i1;
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(これはただのコメントです)
結果的に式は同じになるのですが,個人的にどういう発想なのか気になりました.

for(int m = 0; m < i1; m++){
sum += (A[m] - 1) / i3;
}
return sum > i2;
}

int main(){
int i, lb, ub;
scanf("%d%d", &n, &k);
for(i = 0; i < n; i++){
scanf("%d", &A[i]);
}

lb = 0;
ub = 1000000000;
while(ub - lb >1){
int mid = (lb + ub ) / 2;

if(p(n,k,mid,A) ) lb = mid;
else ub = mid;
}
printf("%d\n", ub);

return 0;
}
22 changes: 16 additions & 6 deletions src/array.c
Original file line number Diff line number Diff line change
@@ -1,18 +1,28 @@
#include <stdio.h>

int n;
int k;
//更新:ファイルを入れ替えました。

int n = 0;
int k = 0;
int A[100000];

int p(int i1,int i2,int X[]){
return X[i2] >= i1;
}

int main(){
int i, lb, ub;
int i, lb, ub = 0;
scanf("%d%d", &n, &k);
for(i = 0; i < n; i++){
scanf("%d", &A[i]);
}



lb = -1;
ub = n;
while(ub - lb > 1){
int mid = (lb + ub) / 2;
if(p(k,mid,A)) ub = mid;
else lb = mid;
}
printf("%d\n", ub);
return 0;
}
19 changes: 18 additions & 1 deletion src/spear.c
Original file line number Diff line number Diff line change
@@ -1,17 +1,34 @@
#include <stdio.h>


//更新:初期値を変更しました。

int n;
int k;
int A[100000];

int p(int i1,int i2, int i3, int X[]){
int sum = 0;
for(int m = 0;m < i1; m++){
sum += X[m] / i3;
}
return sum < i2;
}

int main(){
int i, lb, ub;
scanf("%d%d", &n, &k);
for(i = 0; i < n; i++){
scanf("%d", &A[i]);
}

lb = 0;
ub = 1000000001;
while(ub - lb >1){
int mid = (lb + ub ) / 2;
if(p(n,k,mid,A)) ub = mid;
else lb = mid;
}
printf("%d\n", lb);

return 0;
}
37 changes: 35 additions & 2 deletions src/works.c
Original file line number Diff line number Diff line change
@@ -1,17 +1,50 @@
#include <stdio.h>

//更新:初期値を変更、p関数の不等号を調節しました。

int n;
int k;
int A[100000];

int p(int k1,int k2,int k3, int X[]){
int i1 = 0;
int i2 = 0;
int sum = 0;
while(i2<k1){
sum += X[i2];
if(sum + X[i2 + 1] <= k3){
i2++;
}
else if(sum <= k3 && i2 < k1-1 ){
sum = 0;
i1++;
i2++;
}
else if(sum <= k3 && i2 == k1-1) i1++;
else if(sum > k3) return 0;

}
if(i1 < k2 ) return 1;
else return 0;
}

int main(){
int i, lb, ub;
scanf("%d%d", &n, &k);
for(i = 0; i < n; i++){
scanf("%d", &A[i]);
}


int u = 0;
for(int i = 0;i<n;i++){
u += A[i];
}
lb = 1;
ub = 10000;
while(ub - lb >1){
int mid = ( lb + ub ) / 2;
if(p(n,k,mid,A)) ub = mid;
else lb = mid;
}
printf("%d\n", ub);
return 0;
}